MATH SOLVE

4 months ago

Q:
# At a state fair, there is a game where you throw a ball at a pyramid of cans. If you knock over all of the cans, you win a prize. The cost is 3 throws for $1, but if have you an armband, you get 6 throws for $1. The armband costs $10.i. Write two cost equations for the game in terms of the number of throws purchased, one without an armband and one with.

Accepted Solution

A:

Answer:[tex]y=\frac{1}{3}x[/tex][tex]y=\frac{1}{6}x+10[/tex]Step-by-step explanation:Let x be the number of throws and y be the costWithout armband caseThe cost for 3 throws is $1The cost for 1 throws is [tex]\frac{1}{3}[/tex]The cost for x throws is [tex]\frac{1}{3}x[/tex]So,[tex]y=\frac{1}{3}x[/tex] is the equation for the game in terms of the number of throws purchased without an armband With armband caseThe cost for 6 throws is $1The cost for 1 throws is [tex]\frac{1}{6}[/tex]The cost for x throws is [tex]\frac{1}{6}x[/tex]Cost of Arm band is $10So, Total cost for x throws with arm band = [tex]\frac{1}{6}x+10[/tex]So, [tex]y=\frac{1}{6}x+10[/tex]is the equation for the game in terms of the number of throws purchased with an armband